(x-2)^2-7(x-2)+12=0

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Solution for (x-2)^2-7(x-2)+12=0 equation:



(x-2)^2-7(x-2)+12=0
We multiply parentheses
(x-2)^2-7x+14+12=0
We add all the numbers together, and all the variables
-7x+(x-2)^2+26=0
We move all terms containing x to the left, all other terms to the right
-7x+(x-2)^2=-26

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